Berikut ini adalah kumpulan soal dan pembahasan mengenai limit tingkat SBMPTN. Jika ada jawaban yang salah, mohon dikoreksi melalui komentar. Terima kasih.
No. 11 lim x → 2 x n − 2 n x n 3 − 2 n 3 = 3 16 3 {\displaystyle\lim_{x\to2}\dfrac{x^n-2^n}{x^{\frac{n}3}-2^{\frac{n}3}}=3\sqrt[3]{16}} x → 2 lim x 3 n − 2 3 n x n − 2 n = 3 3 1 6 , tentukan nilai
n n n
CARA 1 : PEMFAKTORAN l i m x → 2 x n − 2 n x n 3 − 2 n 3 = 3163 l i m x → 2 ( x n 3 ) 3 − ( 2 n 3 ) 3 x n 3 − 2 n 3 = 3163 l i m x → 2 ( x n 3 − 2 n 3 ) ( x 2 n 3 + x n 32 n 3 + 22 n 3 ) x n 3 − 2 n 3 = 3163 l i m x → 2 ( x 2 n 3 + x n 32 n 3 + 22 n 3 ) = 316322 n 3 + 2 n 32 n 3 + 22 n 3 = 316322 n 3 + 22 n 3 + 22 n 3 = 31633 ⋅ 22 n 3 = 3163322 n 3 = 316322 n = 162 n = 4 n = 2 limx→2xn−2nxn3−2n3=3163limx→2(xn3)3−(2n3)3xn3−2n3=3163limx→2(xn3−2n3)(x2n3+xn32n3+22n3)xn3−2n3=3163limx→2(x2n3+xn32n3+22n3)=316322n3+2n32n3+22n3=316322n3+22n3+22n3=31633⋅22n3=3163322n3=316322n=162n=4n=2 l i m x → 2 x n − 2 n x n 3 − 2 n 3 = 3 1 6 3 l i m x → 2 ( x n 3 ) 3 − ( 2 n 3 ) 3 x n 3 − 2 n 3 = 3 1 6 3 l i m x → 2 ( x n 3 − 2 n 3 ) ( x 2 n 3 + x n 3 2 n 3 + 2 2 n 3 ) x n 3 − 2 n 3 = 3 1 6 3 l i m x → 2 ( x 2 n 3 + x n 3 2 n 3 + 2 2 n 3 ) = 3 1 6 3 2 2 n 3 + 2 n 3 2 n 3 + 2 2 n 3 = 3 1 6 3 2 2 n 3 + 2 2 n 3 + 2 2 n 3 = 3 1 6 3 3 ⋅ 2 2 n 3 = 3 1 6 3 3 2 2 n 3 = 3 1 6 3 2 2 n = 1 6 2 n = 4 n = 2
CARA 2 : L'HOPITAL l i m x → 2 x n − 2 n x n 3 − 2 n 3 = 3163 l i m x → 2 n x n − 1 n 3 x n 3 − 1 = 3163 l i m x → 23 x n − n 3 = 3163 l i m x → 23 x 2 n 3 = 3163 l i m x → 23 x 2 n 3 = 3163322 n 3 = 316322 n = 162 n = 4 n = 2 limx→2xn−2nxn3−2n3=3163limx→2nxn−1n3xn3−1=3163limx→23xn−n3=3163limx→23x2n3=3163limx→23x2n3=3163322n3=316322n=162n=4n=2 l i m x → 2 x n − 2 n x n 3 − 2 n 3 = 3 1 6 3 l i m x → 2 n x n − 1 n 3 x n 3 − 1 = 3 1 6 3 l i m x → 2 3 x n − n 3 = 3 1 6 3 l i m x → 2 3 x 2 n 3 = 3 1 6 3 l i m x → 2 3 x 2 n 3 = 3 1 6 3 3 2 2 n 3 = 3 1 6 3 2 2 n = 1 6 2 n = 4 n = 2
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